Base | Representation |
---|---|
bin | 111010010100100111100011… |
… | …1000000100011001010001000 |
3 | 2111021102000001001222222110021 |
4 | 1310221033013000203022020 |
5 | 1014220102034042433440 |
6 | 5015024114420030224 |
7 | 213025353416036521 |
oct | 16451170700431210 |
9 | 2437360031888407 |
10 | 513007117546120 |
11 | 13950710787228a |
12 | 49654271832374 |
13 | 19033495b00052 |
14 | 9097969879848 |
15 | 3e4975bd6c84a |
hex | 1d293c7023288 |
513007117546120 has 16 divisors (see below), whose sum is σ = 1154266014478860. Its totient is φ = 205202847018432.
The previous prime is 513007117546097. The next prime is 513007117546139. The reversal of 513007117546120 is 21645711700315.
It can be written as a sum of positive squares in 2 ways, for example, as 494930521797156 + 18076595748964 = 22247034^2 + 4251658^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6412588969287 + ... + 6412588969366.
Almost surely, 2513007117546120 is an apocalyptic number.
It is an amenable number.
513007117546120 is an abundant number, since it is smaller than the sum of its proper divisors (641258896932740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
513007117546120 is a wasteful number, since it uses less digits than its factorization.
513007117546120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12825177938664 (or 12825177938660 counting only the distinct ones).
The product of its (nonzero) digits is 176400, while the sum is 43.
The spelling of 513007117546120 in words is "five hundred thirteen trillion, seven billion, one hundred seventeen million, five hundred forty-six thousand, one hundred twenty".
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