Base | Representation |
---|---|
bin | 101111110001110000… |
… | …111010110011011001 |
3 | 11220102020110021211122 |
4 | 233301300322303121 |
5 | 1320030444214311 |
6 | 35322305335025 |
7 | 3464165243045 |
oct | 576160726331 |
9 | 156366407748 |
10 | 51300773081 |
11 | 1a835a49128 |
12 | 9b38637475 |
13 | 4ab73b883c |
14 | 26a93b3025 |
15 | 1503b890db |
hex | bf1c3acd9 |
51300773081 has 2 divisors, whose sum is σ = 51300773082. Its totient is φ = 51300773080.
The previous prime is 51300773009. The next prime is 51300773087. The reversal of 51300773081 is 18037700315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46390267456 + 4910505625 = 215384^2 + 70075^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51300773081 is a prime.
It is a super-2 number, since 2×513007730812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51300773087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25650386540 + 25650386541.
It is an arithmetic number, because the mean of its divisors is an integer number (25650386541).
Almost surely, 251300773081 is an apocalyptic number.
It is an amenable number.
51300773081 is a deficient number, since it is larger than the sum of its proper divisors (1).
51300773081 is an equidigital number, since it uses as much as digits as its factorization.
51300773081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17640, while the sum is 35.
The spelling of 51300773081 in words is "fifty-one billion, three hundred million, seven hundred seventy-three thousand, eighty-one".
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