Base | Representation |
---|---|
bin | 100101010100111011111… |
… | …0001100100101111000011 |
3 | 200011102221111012120001122 |
4 | 1022221313301210233003 |
5 | 1133023122302420101 |
6 | 14524440451422455 |
7 | 1036434102130034 |
oct | 112516761445703 |
9 | 20142844176048 |
10 | 5130200435651 |
11 | 16a8784446995 |
12 | 6aa3258b4a2b |
13 | 2b2a11646475 |
14 | 13a435708a8b |
15 | 8d6ace7851b |
hex | 4aa77c64bc3 |
5130200435651 has 2 divisors, whose sum is σ = 5130200435652. Its totient is φ = 5130200435650.
The previous prime is 5130200435641. The next prime is 5130200435749. The reversal of 5130200435651 is 1565340020315.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5130200435651 is a prime.
It is not a weakly prime, because it can be changed into another prime (5130200435641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565100217825 + 2565100217826.
It is an arithmetic number, because the mean of its divisors is an integer number (2565100217826).
Almost surely, 25130200435651 is an apocalyptic number.
5130200435651 is a deficient number, since it is larger than the sum of its proper divisors (1).
5130200435651 is an equidigital number, since it uses as much as digits as its factorization.
5130200435651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 5130200435651 its reverse (1565340020315), we get a palindrome (6695540455966).
The spelling of 5130200435651 in words is "five trillion, one hundred thirty billion, two hundred million, four hundred thirty-five thousand, six hundred fifty-one".
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