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51304033364113 is a prime number
BaseRepresentation
bin10111010101001001001101…
…01011110010100010010001
320201122121200021222211210001
423222210212223302202101
523211031130020122423
6301040425250010001
713543410526215535
oct1352444653624221
9221577607884701
1051304033364113
111538aa11382452
125907094b76901
132281c463210aa
14c951b270dbc5
155de807beacad
hex2ea926af2891

51304033364113 has 2 divisors, whose sum is σ = 51304033364114. Its totient is φ = 51304033364112.

The previous prime is 51304033364057. The next prime is 51304033364117. The reversal of 51304033364113 is 31146333040315.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46193390951184 + 5110642412929 = 6796572^2 + 2260673^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51304033364113 is a prime.

It is not a weakly prime, because it can be changed into another prime (51304033364117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25652016682056 + 25652016682057.

It is an arithmetic number, because the mean of its divisors is an integer number (25652016682057).

Almost surely, 251304033364113 is an apocalyptic number.

It is an amenable number.

51304033364113 is a deficient number, since it is larger than the sum of its proper divisors (1).

51304033364113 is an equidigital number, since it uses as much as digits as its factorization.

51304033364113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 116640, while the sum is 37.

The spelling of 51304033364113 in words is "fifty-one trillion, three hundred four billion, thirty-three million, three hundred sixty-four thousand, one hundred thirteen".