Base | Representation |
---|---|
bin | 1110111011100111011… |
… | …00110101001100111011 |
3 | 1211001020210111011112010 |
4 | 13131303230311030323 |
5 | 31401202303142230 |
6 | 1031404403421003 |
7 | 52031444042523 |
oct | 7356354651473 |
9 | 1731223434463 |
10 | 513042240315 |
11 | 188641a73700 |
12 | 83520984763 |
13 | 394c21bbc37 |
14 | 1ab8d426683 |
15 | d52ab2a9b0 |
hex | 7773b3533b |
513042240315 has 96 divisors (see below), whose sum is σ = 958619269440. Its totient is φ = 233678269440.
The previous prime is 513042240301. The next prime is 513042240331.
513042240315 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 513042240315 - 213 = 513042232123 is a prime.
It is a super-4 number, since 4×5130422403154 (a number of 48 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1815777 + ... + 2079213.
It is an arithmetic number, because the mean of its divisors is an integer number (9985617390).
Almost surely, 2513042240315 is an apocalyptic number.
513042240315 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
513042240315 is a deficient number, since it is larger than the sum of its proper divisors (445577029125).
513042240315 is a wasteful number, since it uses less digits than its factorization.
513042240315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 263533 (or 263522 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
It can be divided in two parts, 513042 and 240315, that added together give a palindrome (753357).
The spelling of 513042240315 in words is "five hundred thirteen billion, forty-two million, two hundred forty thousand, three hundred fifteen".
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