Base | Representation |
---|---|
bin | 1001100011101010… |
… | …00001001110111001 |
3 | 111020120210020120221 |
4 | 10301311001032321 |
5 | 41002010341221 |
6 | 2205050020041 |
7 | 241102231423 |
oct | 46165011671 |
9 | 14216706527 |
10 | 5130949561 |
11 | 21a3318391 |
12 | bb2417621 |
13 | 63a01a63a |
14 | 36962b813 |
15 | 2006c1541 |
hex | 131d413b9 |
5130949561 has 2 divisors, whose sum is σ = 5130949562. Its totient is φ = 5130949560.
The previous prime is 5130949517. The next prime is 5130949651. The reversal of 5130949561 is 1659490315.
5130949561 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (5130949651) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4552065961 + 578883600 = 67469^2 + 24060^2 .
It is a cyclic number.
It is not a de Polignac number, because 5130949561 - 29 = 5130949049 is a prime.
It is not a weakly prime, because it can be changed into another prime (5130949511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565474780 + 2565474781.
It is an arithmetic number, because the mean of its divisors is an integer number (2565474781).
Almost surely, 25130949561 is an apocalyptic number.
It is an amenable number.
5130949561 is a deficient number, since it is larger than the sum of its proper divisors (1).
5130949561 is an equidigital number, since it uses as much as digits as its factorization.
5130949561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145800, while the sum is 43.
The square root of 5130949561 is about 71630.6468000953. The cubic root of 5130949561 is about 1724.7755289793.
The spelling of 5130949561 in words is "five billion, one hundred thirty million, nine hundred forty-nine thousand, five hundred sixty-one".
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