Base | Representation |
---|---|
bin | 1110111011101111100… |
… | …11010010000011001001 |
3 | 1211001102120221120020001 |
4 | 13131313303102003021 |
5 | 31401322411241301 |
6 | 1031415302203001 |
7 | 52033240610344 |
oct | 7356763220311 |
9 | 1731376846201 |
10 | 513111040201 |
11 | 188677895011 |
12 | 8353ba23461 |
13 | 3950352a426 |
14 | 1ab9861545b |
15 | d531bbac01 |
hex | 7777cd20c9 |
513111040201 has 2 divisors, whose sum is σ = 513111040202. Its totient is φ = 513111040200.
The previous prime is 513111040181. The next prime is 513111040259. The reversal of 513111040201 is 102040111315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 499735886400 + 13375153801 = 706920^2 + 115651^2 .
It is a cyclic number.
It is not a de Polignac number, because 513111040201 - 227 = 512976822473 is a prime.
It is not a weakly prime, because it can be changed into another prime (513111040301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256555520100 + 256555520101.
It is an arithmetic number, because the mean of its divisors is an integer number (256555520101).
Almost surely, 2513111040201 is an apocalyptic number.
It is an amenable number.
513111040201 is a deficient number, since it is larger than the sum of its proper divisors (1).
513111040201 is an equidigital number, since it uses as much as digits as its factorization.
513111040201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 513111040201 its reverse (102040111315), we get a palindrome (615151151516).
The spelling of 513111040201 in words is "five hundred thirteen billion, one hundred eleven million, forty thousand, two hundred one".
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