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51311135403 = 32113797136501
BaseRepresentation
bin101111110010011000…
…011100101010101011
311220102221221202021100
4233302120130222223
51320041122313103
635323315412443
73464352311643
oct576230345253
9156387852240
1051311135403
111a840886530
129b3bbb4123
134ab95a62a8
1426aa90d523
151504a345a3
hexbf261caab

51311135403 has 24 divisors (see below), whose sum is σ = 80875796976. Its totient is φ = 31089240000.

The previous prime is 51311135357. The next prime is 51311135431. The reversal of 51311135403 is 30453111315.

It is a happy number.

51311135403 is a `hidden beast` number, since 5 + 1 + 3 + 1 + 113 + 540 + 3 = 666.

It is not a de Polignac number, because 51311135403 - 213 = 51311127211 is a prime.

It is not an unprimeable number, because it can be changed into a prime (51311135453) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 307653 + ... + 444153.

It is an arithmetic number, because the mean of its divisors is an integer number (3369824874).

Almost surely, 251311135403 is an apocalyptic number.

51311135403 is a deficient number, since it is larger than the sum of its proper divisors (29564661573).

51311135403 is a wasteful number, since it uses less digits than its factorization.

51311135403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140315 (or 140312 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 27.

Adding to 51311135403 its reverse (30453111315), we get a palindrome (81764246718).

The spelling of 51311135403 in words is "fifty-one billion, three hundred eleven million, one hundred thirty-five thousand, four hundred three".

Divisors: 1 3 9 11 33 99 3797 11391 34173 41767 125301 136501 375903 409503 1228509 1501511 4504533 13513599 518294297 1554882891 4664648673 5701237267 17103711801 51311135403