5131140712501 has 4 divisors (see below), whose sum is σ = 5131145722752. Its totient is φ = 5131135702252.

The previous prime is 5131140712499. The next prime is 5131140712601. The reversal of 5131140712501 is 1052170411315.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 5131140712501 - 2¹ = 5131140712499 is a prime.

It is a super-3 number, since 3×5131140712501³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5131140712001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352165 + ... + 3222778.

It is an arithmetic number, because the mean of its divisors is an integer number (1282786430688).

Almost surely, 2^{5131140712501} is an apocalyptic number.

It is an amenable number.

5131140712501 is a deficient number, since it is larger than the sum of its proper divisors (5010251).

5131140712501 is a wasteful number, since it uses less digits than its factorization.

5131140712501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5010250.

The product of its (nonzero) digits is 4200, while the sum is 31.

The spelling of 5131140712501 in words is "five trillion, one hundred thirty-one billion, one hundred forty million, seven hundred twelve thousand, five hundred one".