Base | Representation |
---|---|
bin | 100101010101011000001… |
… | …0111111111110010011001 |
3 | 200011112101200001001101201 |
4 | 1022222300113333302121 |
5 | 1133032043402011100 |
6 | 14525115012514201 |
7 | 1036466452432423 |
oct | 112526027776231 |
9 | 20145350031351 |
10 | 5131150032025 |
11 | 16a9121473786 |
12 | 6aa54b91b961 |
13 | 2b2b332b6604 |
14 | 13a4c5895813 |
15 | 8d71650036a |
hex | 4aab05ffc99 |
5131150032025 has 48 divisors (see below), whose sum is σ = 6955074989568. Its totient is φ = 3738365568000.
The previous prime is 5131150031989. The next prime is 5131150032067. The reversal of 5131150032025 is 5202300511315.
It is not a de Polignac number, because 5131150032025 - 27 = 5131150031897 is a prime.
It is a super-3 number, since 3×51311500320253 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5131150031984 and 5131150032002.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 136118430 + ... + 136156120.
It is an arithmetic number, because the mean of its divisors is an integer number (144897395616).
Almost surely, 25131150032025 is an apocalyptic number.
It is an amenable number.
5131150032025 is a deficient number, since it is larger than the sum of its proper divisors (1823924957543).
5131150032025 is a wasteful number, since it uses less digits than its factorization.
5131150032025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48082 (or 48077 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 28.
The spelling of 5131150032025 in words is "five trillion, one hundred thirty-one billion, one hundred fifty million, thirty-two thousand, twenty-five".
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