Base | Representation |
---|---|
bin | 1001100011101011… |
… | …10010010011001001 |
3 | 111020121011110021111 |
4 | 10301311302103021 |
5 | 41002033304122 |
6 | 2205054210321 |
7 | 241104026362 |
oct | 46165622311 |
9 | 14217143244 |
10 | 5131150537 |
11 | 21a3445387 |
12 | bb24b39a1 |
13 | 63a08ac66 |
14 | 369680b69 |
15 | 200710d77 |
hex | 131d724c9 |
5131150537 has 2 divisors, whose sum is σ = 5131150538. Its totient is φ = 5131150536.
The previous prime is 5131150529. The next prime is 5131150573. The reversal of 5131150537 is 7350511315.
Together with next prime (5131150573) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4983795216 + 147355321 = 70596^2 + 12139^2 .
It is a cyclic number.
It is not a de Polignac number, because 5131150537 - 23 = 5131150529 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5131150499 and 5131150508.
It is not a weakly prime, because it can be changed into another prime (5131150517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565575268 + 2565575269.
It is an arithmetic number, because the mean of its divisors is an integer number (2565575269).
Almost surely, 25131150537 is an apocalyptic number.
It is an amenable number.
5131150537 is a deficient number, since it is larger than the sum of its proper divisors (1).
5131150537 is an equidigital number, since it uses as much as digits as its factorization.
5131150537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7875, while the sum is 31.
The square root of 5131150537 is about 71632.0496495807. The cubic root of 5131150537 is about 1724.7980481353.
The spelling of 5131150537 in words is "five billion, one hundred thirty-one million, one hundred fifty thousand, five hundred thirty-seven".
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