Base | Representation |
---|---|
bin | 100101010101011010010… |
… | …1011010110001100011101 |
3 | 200011112120200212020122011 |
4 | 1022222310223112030131 |
5 | 1133032220341312110 |
6 | 14525130111551221 |
7 | 1036501320112651 |
oct | 112526453261435 |
9 | 20145520766564 |
10 | 5131222213405 |
11 | 16a9159194712 |
12 | 6aa56bb2b511 |
13 | 2b2b45239ca2 |
14 | 13a4d12c4a61 |
15 | 8d71ca0c48a |
hex | 4aab4ad631d |
5131222213405 has 16 divisors (see below), whose sum is σ = 6207748485120. Its totient is φ = 4071475279872.
The previous prime is 5131222213387. The next prime is 5131222213451. The reversal of 5131222213405 is 5043122221315.
It is a happy number.
5131222213405 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5131222213405 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1026456 + ... + 3363934.
It is an arithmetic number, because the mean of its divisors is an integer number (387984280320).
Almost surely, 25131222213405 is an apocalyptic number.
It is an amenable number.
5131222213405 is a deficient number, since it is larger than the sum of its proper divisors (1076526271715).
5131222213405 is a wasteful number, since it uses less digits than its factorization.
5131222213405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2341068.
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 5131222213405 in words is "five trillion, one hundred thirty-one billion, two hundred twenty-two million, two hundred thirteen thousand, four hundred five".
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