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513136654425281 is a prime number
BaseRepresentation
bin111010010101100011111000…
…0000000100001110011000001
32111021212101101201111020201102
41310223013300000201303001
51014224212332013102111
65015203420312544145
7213040620440246405
oct16453076000416301
92437771351436642
10513136654425281
1113955703aa83917
12496753a33b2055
131904276aa62983
14909dd3762d105
153e4ccde20013b
hex1d2b1f0021cc1

513136654425281 has 2 divisors, whose sum is σ = 513136654425282. Its totient is φ = 513136654425280.

The previous prime is 513136654425257. The next prime is 513136654425323. The reversal of 513136654425281 is 182524456631315.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 332669000294656 + 180467654130625 = 18239216^2 + 13433825^2 .

It is a cyclic number.

It is not a de Polignac number, because 513136654425281 - 238 = 512861776518337 is a prime.

It is a super-2 number, since 2×5131366544252812 (a number of 30 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (513136653425281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256568327212640 + 256568327212641.

It is an arithmetic number, because the mean of its divisors is an integer number (256568327212641).

Almost surely, 2513136654425281 is an apocalyptic number.

It is an amenable number.

513136654425281 is a deficient number, since it is larger than the sum of its proper divisors (1).

513136654425281 is an equidigital number, since it uses as much as digits as its factorization.

513136654425281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 20736000, while the sum is 56.

The spelling of 513136654425281 in words is "five hundred thirteen trillion, one hundred thirty-six billion, six hundred fifty-four million, four hundred twenty-five thousand, two hundred eighty-one".