Base | Representation |
---|---|
bin | 111010010110000001111010… |
… | …0010101011011011101000111 |
3 | 2111022002112212122011021021202 |
4 | 1310230003310111123131013 |
5 | 1014231241424242211011 |
6 | 5015253204305333115 |
7 | 213045362644445165 |
oct | 16454036425333507 |
9 | 2438075778137252 |
10 | 513201151522631 |
11 | 1395814279a9760 |
12 | 496859a333719b |
13 | 190488790bb3c0 |
14 | 90a30d5474235 |
15 | 3e4e81666b23b |
hex | 1d2c0f455b747 |
513201151522631 has 16 divisors (see below), whose sum is σ = 638387610946848. Its totient is φ = 405325467264000.
The previous prime is 513201151522627. The next prime is 513201151522643. The reversal of 513201151522631 is 136225151102315.
It is a cyclic number.
It is not a de Polignac number, because 513201151522631 - 22 = 513201151522627 is a prime.
It is a super-2 number, since 2×5132011515226312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513201151522601) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 105553504670 + ... + 105553509531.
It is an arithmetic number, because the mean of its divisors is an integer number (39899225684178).
Almost surely, 2513201151522631 is an apocalyptic number.
513201151522631 is a deficient number, since it is larger than the sum of its proper divisors (125186459424217).
513201151522631 is a wasteful number, since it uses less digits than its factorization.
513201151522631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211107014242.
The product of its (nonzero) digits is 54000, while the sum is 38.
The spelling of 513201151522631 in words is "five hundred thirteen trillion, two hundred one billion, one hundred fifty-one million, five hundred twenty-two thousand, six hundred thirty-one".
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