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51320546141 = 110346528147
BaseRepresentation
bin101111110010111100…
…010110001101011101
311220110121122212101012
4233302330112031131
51320101024434031
635324253225005
73464525305334
oct576274261535
9156417585335
1051320546141
111a8461239a7
129b43192165
134abb51c887
1426abc7cd1b
151505792b2b
hexbf2f1635d

51320546141 has 4 divisors (see below), whose sum is σ = 51367075392. Its totient is φ = 51274016892.

The previous prime is 51320546099. The next prime is 51320546153. The reversal of 51320546141 is 14164502315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51320546141 - 230 = 50246804317 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51320546098 and 51320546107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51320549141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23262971 + ... + 23265176.

It is an arithmetic number, because the mean of its divisors is an integer number (12841768848).

Almost surely, 251320546141 is an apocalyptic number.

It is an amenable number.

51320546141 is a deficient number, since it is larger than the sum of its proper divisors (46529251).

51320546141 is a wasteful number, since it uses less digits than its factorization.

51320546141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46529250.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 51320546141 in words is "fifty-one billion, three hundred twenty million, five hundred forty-six thousand, one hundred forty-one".

Divisors: 1 1103 46528147 51320546141