Base | Representation |
---|---|
bin | 100101010101110100111… |
… | …0101101100110011100011 |
3 | 200011121212212010210100022 |
4 | 1022223221311230303203 |
5 | 1133041032203314112 |
6 | 14525354412344055 |
7 | 1036532400152315 |
oct | 112535165546343 |
9 | 20147785123308 |
10 | 5132114119907 |
11 | 16a9576699225 |
12 | 6aa77a77502b |
13 | 2b2c57c5b808 |
14 | 13a5779357b5 |
15 | 8d770e8ad72 |
hex | 4aae9d6cce3 |
5132114119907 has 2 divisors, whose sum is σ = 5132114119908. Its totient is φ = 5132114119906.
The previous prime is 5132114119903. The next prime is 5132114119991. The reversal of 5132114119907 is 7099114112315.
5132114119907 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5132114119907 - 22 = 5132114119903 is a prime.
It is not a weakly prime, because it can be changed into another prime (5132114119903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566057059953 + 2566057059954.
It is an arithmetic number, because the mean of its divisors is an integer number (2566057059954).
Almost surely, 25132114119907 is an apocalyptic number.
5132114119907 is a deficient number, since it is larger than the sum of its proper divisors (1).
5132114119907 is an equidigital number, since it uses as much as digits as its factorization.
5132114119907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 44.
The spelling of 5132114119907 in words is "five trillion, one hundred thirty-two billion, one hundred fourteen million, one hundred nineteen thousand, nine hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •