Base | Representation |
---|---|
bin | 1110111011111101111… |
… | …01101011001010010011 |
3 | 1211001201222001120100120 |
4 | 13131332331223022103 |
5 | 31402044142030021 |
6 | 1031435233521323 |
7 | 52036230156150 |
oct | 7357675531223 |
9 | 1731658046316 |
10 | 513231205011 |
11 | 1887296a9678 |
12 | 83574113243 |
13 | 395223b1375 |
14 | 1abaa575227 |
15 | d53c5052c6 |
hex | 777ef6b293 |
513231205011 has 32 divisors (see below), whose sum is σ = 856624688640. Its totient is φ = 266505447936.
The previous prime is 513231204881. The next prime is 513231205027. The reversal of 513231205011 is 110502132315.
It is not a de Polignac number, because 513231205011 - 235 = 478871466643 is a prime.
It is a super-2 number, since 2×5132312050112 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (513231205061) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24776241 + ... + 24796946.
It is an arithmetic number, because the mean of its divisors is an integer number (26769521520).
Almost surely, 2513231205011 is an apocalyptic number.
513231205011 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
513231205011 is a deficient number, since it is larger than the sum of its proper divisors (343393483629).
513231205011 is a wasteful number, since it uses less digits than its factorization.
513231205011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49573243.
The product of its (nonzero) digits is 900, while the sum is 24.
Adding to 513231205011 its reverse (110502132315), we get a palindrome (623733337326).
The spelling of 513231205011 in words is "five hundred thirteen billion, two hundred thirty-one million, two hundred five thousand, eleven".
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