Base | Representation |
---|---|
bin | 10111010101101100111111… |
… | …01000100010000010110011 |
3 | 20201201110021000020010001011 |
4 | 23222312133220202002303 |
5 | 23211340000030004301 |
6 | 301053323322451351 |
7 | 13544660535424216 |
oct | 1352663750420263 |
9 | 221643230203034 |
10 | 51323242422451 |
11 | 1539807939827a |
12 | 590a956063b57 |
13 | 22839b7b97bbc |
14 | c960b594777d |
15 | 5e007e2cda51 |
hex | 2ead9fa220b3 |
51323242422451 has 2 divisors, whose sum is σ = 51323242422452. Its totient is φ = 51323242422450.
The previous prime is 51323242422437. The next prime is 51323242422493. The reversal of 51323242422451 is 15422424232315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51323242422451 - 217 = 51323242291379 is a prime.
It is not a weakly prime, because it can be changed into another prime (51323242420451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25661621211225 + 25661621211226.
It is an arithmetic number, because the mean of its divisors is an integer number (25661621211226).
Almost surely, 251323242422451 is an apocalyptic number.
51323242422451 is a deficient number, since it is larger than the sum of its proper divisors (1).
51323242422451 is an equidigital number, since it uses as much as digits as its factorization.
51323242422451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 460800, while the sum is 40.
Adding to 51323242422451 its reverse (15422424232315), we get a palindrome (66745666654766).
The spelling of 51323242422451 in words is "fifty-one trillion, three hundred twenty-three billion, two hundred forty-two million, four hundred twenty-two thousand, four hundred fifty-one".
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