Base | Representation |
---|---|
bin | 111010010110010101000011… |
… | …0000111111000100011100011 |
3 | 2111022020110222000020112002022 |
4 | 1310230222012013320203203 |
5 | 1014232430113022313021 |
6 | 5015324122522412055 |
7 | 213051346315150115 |
oct | 16454520607704343 |
9 | 2438213860215068 |
10 | 513242252151011 |
11 | 1395978a9161129 |
12 | 4969195396102b |
13 | 1904c6c91b1656 |
14 | 90a50b3ca53b5 |
15 | 3e5091eab01ab |
hex | 1d2ca861f88e3 |
513242252151011 has 2 divisors, whose sum is σ = 513242252151012. Its totient is φ = 513242252151010.
The previous prime is 513242252150993. The next prime is 513242252151037. The reversal of 513242252151011 is 110151252242315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 513242252151011 - 230 = 513241178409187 is a prime.
It is not a weakly prime, because it can be changed into another prime (513242252151511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256621126075505 + 256621126075506.
It is an arithmetic number, because the mean of its divisors is an integer number (256621126075506).
Almost surely, 2513242252151011 is an apocalyptic number.
513242252151011 is a deficient number, since it is larger than the sum of its proper divisors (1).
513242252151011 is an equidigital number, since it uses as much as digits as its factorization.
513242252151011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 35.
The spelling of 513242252151011 in words is "five hundred thirteen trillion, two hundred forty-two billion, two hundred fifty-two million, one hundred fifty-one thousand, eleven".
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