Base | Representation |
---|---|
bin | 100101010110001111101… |
… | …1110101011100111111101 |
3 | 200011201012120112020210021 |
4 | 1022230133132223213331 |
5 | 1133044403044233141 |
6 | 14530024001212141 |
7 | 1036563605402110 |
oct | 112543736534775 |
9 | 20151176466707 |
10 | 5133014055421 |
11 | 16a999868708a |
12 | 6aa990031051 |
13 | 2b306c531a35 |
14 | 13a621276577 |
15 | 8d7c4ea36d1 |
hex | 4ab1f7ab9fd |
5133014055421 has 8 divisors (see below), whose sum is σ = 5866408632960. Its totient is φ = 4399646191728.
The previous prime is 5133014055383. The next prime is 5133014055503. The reversal of 5133014055421 is 1245504103315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5133014055421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5133014055121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6265006 + ... + 7036783.
It is an arithmetic number, because the mean of its divisors is an integer number (733301079120).
Almost surely, 25133014055421 is an apocalyptic number.
It is an amenable number.
5133014055421 is a deficient number, since it is larger than the sum of its proper divisors (733394577539).
5133014055421 is a wasteful number, since it uses less digits than its factorization.
5133014055421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13356923.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 5133014055421 its reverse (1245504103315), we get a palindrome (6378518158736).
The spelling of 5133014055421 in words is "five trillion, one hundred thirty-three billion, fourteen million, fifty-five thousand, four hundred twenty-one".
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