Base | Representation |
---|---|
bin | 100101010110010000000… |
… | …0101011111111100101101 |
3 | 200011201020021200020100110 |
4 | 1022230200011133330231 |
5 | 1133044413200344323 |
6 | 14530025003250233 |
7 | 1036564061033124 |
oct | 112544005377455 |
9 | 20151207606313 |
10 | 5133024231213 |
11 | 16a99a33a732a |
12 | 6aa993519979 |
13 | 2b3071685608 |
14 | 13a622764abb |
15 | 8d7c5d13793 |
hex | 4ab2015ff2d |
5133024231213 has 4 divisors (see below), whose sum is σ = 6844032308288. Its totient is φ = 3422016154140.
The previous prime is 5133024231187. The next prime is 5133024231217. The reversal of 5133024231213 is 3121324203315.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 5133024231213 - 210 = 5133024230189 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5133024231217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 855504038533 + ... + 855504038538.
It is an arithmetic number, because the mean of its divisors is an integer number (1711008077072).
Almost surely, 25133024231213 is an apocalyptic number.
It is an amenable number.
5133024231213 is a deficient number, since it is larger than the sum of its proper divisors (1711008077075).
5133024231213 is a wasteful number, since it uses less digits than its factorization.
5133024231213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1711008077074.
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 5133024231213 its reverse (3121324203315), we get a palindrome (8254348434528).
The spelling of 5133024231213 in words is "five trillion, one hundred thirty-three billion, twenty-four million, two hundred thirty-one thousand, two hundred thirteen".
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