Base | Representation |
---|---|
bin | 101111110011100001… |
… | …100100011000001101 |
3 | 11220111022000120221220 |
4 | 233303201210120031 |
5 | 1320111024203001 |
6 | 35325242313553 |
7 | 3465004244421 |
oct | 576341443015 |
9 | 156438016856 |
10 | 51330303501 |
11 | 1a850688834 |
12 | 9b464b88b9 |
13 | 4ac0557b69 |
14 | 26ad29cb81 |
15 | 150656dc36 |
hex | bf386460d |
51330303501 has 8 divisors (see below), whose sum is σ = 68932782240. Its totient is φ = 33974013552.
The previous prime is 51330303467. The next prime is 51330303551. The reversal of 51330303501 is 10530303315.
51330303501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 51330303501 - 213 = 51330295309 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51330303551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61546710 + ... + 61547543.
It is an arithmetic number, because the mean of its divisors is an integer number (8616597780).
Almost surely, 251330303501 is an apocalyptic number.
It is an amenable number.
51330303501 is a deficient number, since it is larger than the sum of its proper divisors (17602478739).
51330303501 is a wasteful number, since it uses less digits than its factorization.
51330303501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123094395.
The product of its (nonzero) digits is 2025, while the sum is 24.
Adding to 51330303501 its reverse (10530303315), we get a palindrome (61860606816).
The spelling of 51330303501 in words is "fifty-one billion, three hundred thirty million, three hundred three thousand, five hundred one".
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