Base | Representation |
---|---|
bin | 10111010101111111100101… |
… | …00010111101001000001101 |
3 | 20201202102000121012111211010 |
4 | 23222333302202331020031 |
5 | 23212020420142412140 |
6 | 301102053545515433 |
7 | 13545463062366012 |
oct | 1352776242751015 |
9 | 221672017174733 |
10 | 51333223404045 |
11 | 153a13303a24a0 |
12 | 59108807a2b79 |
13 | 228491895697b |
14 | c96781359709 |
15 | 5e0465681880 |
hex | 2eaff28bd20d |
51333223404045 has 32 divisors (see below), whose sum is σ = 89610252246144. Its totient is φ = 24885934444800.
The previous prime is 51333223404037. The next prime is 51333223404061. The reversal of 51333223404045 is 54040432233315.
It is not a de Polignac number, because 51333223404045 - 23 = 51333223404037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51333223403994 and 51333223404012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16712002 + ... + 19543731.
It is an arithmetic number, because the mean of its divisors is an integer number (2800320382692).
Almost surely, 251333223404045 is an apocalyptic number.
51333223404045 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
51333223404045 is a deficient number, since it is larger than the sum of its proper divisors (38277028842099).
51333223404045 is a wasteful number, since it uses less digits than its factorization.
51333223404045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36264333.
The product of its (nonzero) digits is 518400, while the sum is 39.
The spelling of 51333223404045 in words is "fifty-one trillion, three hundred thirty-three billion, two hundred twenty-three million, four hundred four thousand, forty-five".
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