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51334043044 = 2213197965731
BaseRepresentation
bin101111110011101111…
…110101010110100100
311220111120001120122111
4233303233311112210
51320113003334134
635325454410404
73465051111034
oct576357652644
9156446046574
1051334043044
111a852802369
129b47800a04
134ac1266ccb
1426ad9938c4
151506a5bc64
hexbf3bf55a4

51334043044 has 12 divisors (see below), whose sum is σ = 90520336368. Its totient is φ = 25471089800.

The previous prime is 51334043011. The next prime is 51334043077. The reversal of 51334043044 is 44034043315.

It is an interprime number because it is at equal distance from previous prime (51334043011) and next prime (51334043077).

It is a junction number, because it is equal to n+sod(n) for n = 51334042997 and 51334043015.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48982342 + ... + 48983389.

It is an arithmetic number, because the mean of its divisors is an integer number (7543361364).

Almost surely, 251334043044 is an apocalyptic number.

It is an amenable number.

51334043044 is a deficient number, since it is larger than the sum of its proper divisors (39186293324).

51334043044 is a wasteful number, since it uses less digits than its factorization.

51334043044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 97965866 (or 97965864 counting only the distinct ones).

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 51334043044 its reverse (44034043315), we get a palindrome (95368086359).

The spelling of 51334043044 in words is "fifty-one billion, three hundred thirty-four million, forty-three thousand, forty-four".

Divisors: 1 2 4 131 262 524 97965731 195931462 391862924 12833510761 25667021522 51334043044