Base | Representation |
---|---|
bin | 101111110011110000… |
… | …000100110110000001 |
3 | 11220111120011210200121 |
4 | 233303300010312001 |
5 | 1320113012401442 |
6 | 35325500020241 |
7 | 3465051464032 |
oct | 576360046601 |
9 | 156446153617 |
10 | 51334106497 |
11 | 1a852846003 |
12 | 9b47831681 |
13 | 4ac1289b5b |
14 | 26ad9aca89 |
15 | 1506a70967 |
hex | bf3c04d81 |
51334106497 has 2 divisors, whose sum is σ = 51334106498. Its totient is φ = 51334106496.
The previous prime is 51334106477. The next prime is 51334106507. The reversal of 51334106497 is 79460143315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44882964736 + 6451141761 = 211856^2 + 80319^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51334106497 is a prime.
It is a super-2 number, since 2×513341064972 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51334106407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25667053248 + 25667053249.
It is an arithmetic number, because the mean of its divisors is an integer number (25667053249).
Almost surely, 251334106497 is an apocalyptic number.
It is an amenable number.
51334106497 is a deficient number, since it is larger than the sum of its proper divisors (1).
51334106497 is an equidigital number, since it uses as much as digits as its factorization.
51334106497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 272160, while the sum is 43.
The spelling of 51334106497 in words is "fifty-one billion, three hundred thirty-four million, one hundred six thousand, four hundred ninety-seven".
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