Base | Representation |
---|---|
bin | 1110111100010010001… |
… | …10101010011010111001 |
3 | 1211002011211011222200020 |
4 | 13132021012222122321 |
5 | 31402421220132213 |
6 | 1031504152201053 |
7 | 52043364221322 |
oct | 7361106523271 |
9 | 1732154158606 |
10 | 513401333433 |
11 | 18880673967a |
12 | 83601099189 |
13 | 3954b709c81 |
14 | 1abc4dbd449 |
15 | d54c40d923 |
hex | 77891aa6b9 |
513401333433 has 8 divisors (see below), whose sum is σ = 686871409728. Its totient is φ = 341099406384.
The previous prime is 513401333413. The next prime is 513401333437. The reversal of 513401333433 is 334333104315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 513401333433 - 28 = 513401333177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 513401333394 and 513401333403.
It is not an unprimeable number, because it can be changed into a prime (513401333437) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 292036285 + ... + 292038042.
It is an arithmetic number, because the mean of its divisors is an integer number (85858926216).
Almost surely, 2513401333433 is an apocalyptic number.
It is an amenable number.
513401333433 is a deficient number, since it is larger than the sum of its proper divisors (173470076295).
513401333433 is a wasteful number, since it uses less digits than its factorization.
513401333433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 584074623.
The product of its (nonzero) digits is 58320, while the sum is 33.
Adding to 513401333433 its reverse (334333104315), we get a palindrome (847734437748).
The spelling of 513401333433 in words is "five hundred thirteen billion, four hundred one million, three hundred thirty-three thousand, four hundred thirty-three".
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