Base | Representation |
---|---|
bin | 1110111100010010001… |
… | …10101010011010111101 |
3 | 1211002011211011222200101 |
4 | 13132021012222122331 |
5 | 31402421220132222 |
6 | 1031504152201101 |
7 | 52043364221326 |
oct | 7361106523275 |
9 | 1732154158611 |
10 | 513401333437 |
11 | 188806739683 |
12 | 83601099191 |
13 | 3954b709c85 |
14 | 1abc4dbd44d |
15 | d54c40d927 |
hex | 77891aa6bd |
513401333437 has 2 divisors, whose sum is σ = 513401333438. Its totient is φ = 513401333436.
The previous prime is 513401333413. The next prime is 513401333477. The reversal of 513401333437 is 734333104315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 410856642361 + 102544691076 = 640981^2 + 320226^2 .
It is a cyclic number.
It is not a de Polignac number, because 513401333437 - 215 = 513401300669 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 513401333396 and 513401333405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513401333477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256700666718 + 256700666719.
It is an arithmetic number, because the mean of its divisors is an integer number (256700666719).
Almost surely, 2513401333437 is an apocalyptic number.
It is an amenable number.
513401333437 is a deficient number, since it is larger than the sum of its proper divisors (1).
513401333437 is an equidigital number, since it uses as much as digits as its factorization.
513401333437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 37.
The spelling of 513401333437 in words is "five hundred thirteen billion, four hundred one million, three hundred thirty-three thousand, four hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •