Base | Representation |
---|---|
bin | 1110111100010010001… |
… | …10101010011010100101 |
3 | 1211002011211011222122111 |
4 | 13132021012222122211 |
5 | 31402421220132123 |
6 | 1031504152201021 |
7 | 52043364221263 |
oct | 7361106523245 |
9 | 1732154158574 |
10 | 513401333413 |
11 | 188806739661 |
12 | 83601099171 |
13 | 3954b709c67 |
14 | 1abc4dbd433 |
15 | d54c40d90d |
hex | 77891aa6a5 |
513401333413 has 2 divisors, whose sum is σ = 513401333414. Its totient is φ = 513401333412.
The previous prime is 513401333351. The next prime is 513401333437. The reversal of 513401333413 is 314333104315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 376311087364 + 137090246049 = 613442^2 + 370257^2 .
It is a cyclic number.
It is not a de Polignac number, because 513401333413 - 217 = 513401202341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513401333513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256700666706 + 256700666707.
It is an arithmetic number, because the mean of its divisors is an integer number (256700666707).
Almost surely, 2513401333413 is an apocalyptic number.
It is an amenable number.
513401333413 is a deficient number, since it is larger than the sum of its proper divisors (1).
513401333413 is an equidigital number, since it uses as much as digits as its factorization.
513401333413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 513401333413 its reverse (314333104315), we get a palindrome (827734437728).
The spelling of 513401333413 in words is "five hundred thirteen billion, four hundred one million, three hundred thirty-three thousand, four hundred thirteen".
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