Base | Representation |
---|---|
bin | 10111010110010000111101… |
… | …01101111101010110000011 |
3 | 20201210022002220011021012021 |
4 | 23223020132231331112003 |
5 | 23212144022412424421 |
6 | 301110235513542311 |
7 | 13546243234620646 |
oct | 1353103655752603 |
9 | 221708086137167 |
10 | 51342554420611 |
11 | 153a5289522333 |
12 | 5912645714997 |
13 | 2285774b7464c |
14 | c96dc86d9a5d |
15 | 5e080e947341 |
hex | 2eb21eb7d583 |
51342554420611 has 2 divisors, whose sum is σ = 51342554420612. Its totient is φ = 51342554420610.
The previous prime is 51342554420587. The next prime is 51342554420617. The reversal of 51342554420611 is 11602445524315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51342554420611 - 215 = 51342554387843 is a prime.
It is a super-2 number, since 2×513425544206112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51342554420617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25671277210305 + 25671277210306.
It is an arithmetic number, because the mean of its divisors is an integer number (25671277210306).
Almost surely, 251342554420611 is an apocalyptic number.
51342554420611 is a deficient number, since it is larger than the sum of its proper divisors (1).
51342554420611 is an equidigital number, since it uses as much as digits as its factorization.
51342554420611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576000, while the sum is 43.
Adding to 51342554420611 its reverse (11602445524315), we get a palindrome (62944999944926).
The spelling of 51342554420611 in words is "fifty-one trillion, three hundred forty-two billion, five hundred fifty-four million, four hundred twenty thousand, six hundred eleven".
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