Base | Representation |
---|---|
bin | 10111010110010101101000… |
… | …10011010010011001000011 |
3 | 20201210112120210101200110201 |
4 | 23223022310103102121003 |
5 | 23212214142341330311 |
6 | 301111332523110031 |
7 | 13546362360032656 |
oct | 1353126423223103 |
9 | 221715523350421 |
10 | 51345064011331 |
11 | 153a6357086a52 |
12 | 5913026072317 |
13 | 2285a84a8127c |
14 | c97185b2589d |
15 | 5e0909e199c1 |
hex | 2eb2b44d2643 |
51345064011331 has 2 divisors, whose sum is σ = 51345064011332. Its totient is φ = 51345064011330.
The previous prime is 51345064011317. The next prime is 51345064011359. The reversal of 51345064011331 is 13311046054315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51345064011331 - 237 = 51207625057859 is a prime.
It is a super-3 number, since 3×513450640113313 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (51345064011361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25672532005665 + 25672532005666.
It is an arithmetic number, because the mean of its divisors is an integer number (25672532005666).
Almost surely, 251345064011331 is an apocalyptic number.
51345064011331 is a deficient number, since it is larger than the sum of its proper divisors (1).
51345064011331 is an equidigital number, since it uses as much as digits as its factorization.
51345064011331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 51345064011331 in words is "fifty-one trillion, three hundred forty-five billion, sixty-four million, eleven thousand, three hundred thirty-one".
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