Base | Representation |
---|---|
bin | 111010010111110111011010… |
… | …0010100101000000010111011 |
3 | 2111022222200011212220120202011 |
4 | 1310233232310110220002323 |
5 | 1014244410212021000244 |
6 | 5020005134522150351 |
7 | 213102534621532504 |
oct | 16457566424500273 |
9 | 2438880155816664 |
10 | 513453480640699 |
11 | 139669442131875 |
12 | 497068839523b7 |
13 | 190665bc878b61 |
14 | 90b13d1333bab |
15 | 3e56183ba9434 |
hex | 1d2fbb45280bb |
513453480640699 has 2 divisors, whose sum is σ = 513453480640700. Its totient is φ = 513453480640698.
The previous prime is 513453480640643. The next prime is 513453480640733. The reversal of 513453480640699 is 996046084354315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 513453480640699 - 213 = 513453480632507 is a prime.
It is not a weakly prime, because it can be changed into another prime (513453480640619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256726740320349 + 256726740320350.
It is an arithmetic number, because the mean of its divisors is an integer number (256726740320350).
Almost surely, 2513453480640699 is an apocalyptic number.
513453480640699 is a deficient number, since it is larger than the sum of its proper divisors (1).
513453480640699 is an equidigital number, since it uses as much as digits as its factorization.
513453480640699 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 335923200, while the sum is 67.
The spelling of 513453480640699 in words is "five hundred thirteen trillion, four hundred fifty-three billion, four hundred eighty million, six hundred forty thousand, six hundred ninety-nine".
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