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51349993 is a prime number
BaseRepresentation
bin1100001111100…
…0100111101001
310120121211221121
43003320213221
5101121144433
65032335241
71162316302
oct303704751
9116554847
1051349993
1126a93012
1215244521
13a83ba16
146b697a9
154794c2d
hex30f89e9

51349993 has 2 divisors, whose sum is σ = 51349994. Its totient is φ = 51349992.

The previous prime is 51349967. The next prime is 51350003. The reversal of 51349993 is 39994315.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47155689 + 4194304 = 6867^2 + 2048^2 .

It is a cyclic number.

It is not a de Polignac number, because 51349993 - 29 = 51349481 is a prime.

It is a super-2 number, since 2×513499932 = 5273643562200098, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51349943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25674996 + 25674997.

It is an arithmetic number, because the mean of its divisors is an integer number (25674997).

Almost surely, 251349993 is an apocalyptic number.

It is an amenable number.

51349993 is a deficient number, since it is larger than the sum of its proper divisors (1).

51349993 is an equidigital number, since it uses as much as digits as its factorization.

51349993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 131220, while the sum is 43.

The square root of 51349993 is about 7165.8909425137. The cubic root of 51349993 is about 371.6893603773.

The spelling of 51349993 in words is "fifty-one million, three hundred forty-nine thousand, nine hundred ninety-three".