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51350611243307 is a prime number
BaseRepresentation
bin10111010110011111111101…
…11100010011000100101011
320201211001220101111021011212
423223033332330103010223
523212312022434241212
6301114051203343335
713546650005522645
oct1353177674230453
9221731811437155
1051350611243307
11153a8743380492
125914113981b4b
13228645a0c145c
14c97550755895
155e0b31e18e22
hex2eb3fef1312b

51350611243307 has 2 divisors, whose sum is σ = 51350611243308. Its totient is φ = 51350611243306.

The previous prime is 51350611243297. The next prime is 51350611243381. The reversal of 51350611243307 is 70334211605315.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51350611243307 - 224 = 51350594466091 is a prime.

It is a super-2 number, since 2×513506112433072 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51350611243807) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25675305621653 + 25675305621654.

It is an arithmetic number, because the mean of its divisors is an integer number (25675305621654).

Almost surely, 251350611243307 is an apocalyptic number.

51350611243307 is a deficient number, since it is larger than the sum of its proper divisors (1).

51350611243307 is an equidigital number, since it uses as much as digits as its factorization.

51350611243307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 41.

The spelling of 51350611243307 in words is "fifty-one trillion, three hundred fifty billion, six hundred eleven million, two hundred forty-three thousand, three hundred seven".