Base | Representation |
---|---|
bin | 100101010111001110010… |
… | …0010001001010001110011 |
3 | 200011220121210101201220021 |
4 | 1022232130202021101303 |
5 | 1133113202200142230 |
6 | 14531012110024311 |
7 | 1036666602535600 |
oct | 112563442112163 |
9 | 20156553351807 |
10 | 5135112115315 |
11 | 16aa874a0a586 |
12 | 6ab2767a8097 |
13 | 2b33150c07b0 |
14 | 13a77db796a7 |
15 | 8d899285c7a |
hex | 4ab9c889473 |
5135112115315 has 48 divisors (see below), whose sum is σ = 7728608920032. Its totient is φ = 3246562238976.
The previous prime is 5135112115313. The next prime is 5135112115351.
5135112115315 is nontrivially palindromic in base 10.
5135112115315 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5135112115315 - 21 = 5135112115313 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5135112115313) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1788892 + ... + 3670198.
It is an arithmetic number, because the mean of its divisors is an integer number (161012685834).
Almost surely, 25135112115315 is an apocalyptic number.
5135112115315 is a deficient number, since it is larger than the sum of its proper divisors (2593496804717).
5135112115315 is a wasteful number, since it uses less digits than its factorization.
5135112115315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1882196 (or 1882189 counting only the distinct ones).
The product of its digits is 11250, while the sum is 34.
The spelling of 5135112115315 in words is "five trillion, one hundred thirty-five billion, one hundred twelve million, one hundred fifteen thousand, three hundred fifteen".
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