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513511245252241 is a prime number
BaseRepresentation
bin111010011000010010010011…
…1010111001000011010010001
32111100012012021121012220000021
41310300210213113020122101
51014301332012241032431
65020051450454223441
7213106651235610625
oct16460444727103221
92440165247186007
10513511245252241
11139690994809455
1249715b05054b81
131906bb97163b82
1490b4110d77185
153e5791504eb11
hex1d309275c8691

513511245252241 has 2 divisors, whose sum is σ = 513511245252242. Its totient is φ = 513511245252240.

The previous prime is 513511245252211. The next prime is 513511245252353. The reversal of 513511245252241 is 142252542115315.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 493358328612241 + 20152916640000 = 22211671^2 + 4489200^2 .

It is a cyclic number.

It is not a de Polignac number, because 513511245252241 - 219 = 513511244727953 is a prime.

It is not a weakly prime, because it can be changed into another prime (513511245252211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256755622626120 + 256755622626121.

It is an arithmetic number, because the mean of its divisors is an integer number (256755622626121).

Almost surely, 2513511245252241 is an apocalyptic number.

It is an amenable number.

513511245252241 is a deficient number, since it is larger than the sum of its proper divisors (1).

513511245252241 is an equidigital number, since it uses as much as digits as its factorization.

513511245252241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 480000, while the sum is 43.

Adding to 513511245252241 its reverse (142252542115315), we get a palindrome (655763787367556).

The spelling of 513511245252241 in words is "five hundred thirteen trillion, five hundred eleven billion, two hundred forty-five million, two hundred fifty-two thousand, two hundred forty-one".