Search a number
-
+
513511444013 = 2129872410999
BaseRepresentation
bin1110111100011111010…
…10101100111000101101
31211002110111101011222212
413132033222230320231
531403132412202023
61031523124220205
752046202153401
oct7361752547055
91732414334885
10513511444013
11188862906357
1283631b3a665
1339568480769
141abd5883101
15d556e0de78
hex778faace2d

513511444013 has 4 divisors (see below), whose sum is σ = 513514068000. Its totient is φ = 513508820028.

The previous prime is 513511443953. The next prime is 513511444057. The reversal of 513511444013 is 310444115315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-513511444013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (513511444513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 992513 + ... + 1418486.

It is an arithmetic number, because the mean of its divisors is an integer number (128378517000).

Almost surely, 2513511444013 is an apocalyptic number.

It is an amenable number.

513511444013 is a deficient number, since it is larger than the sum of its proper divisors (2623987).

513511444013 is a wasteful number, since it uses less digits than its factorization.

513511444013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2623986.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 513511444013 its reverse (310444115315), we get a palindrome (823955559328).

The spelling of 513511444013 in words is "five hundred thirteen billion, five hundred eleven million, four hundred forty-four thousand, thirteen".

Divisors: 1 212987 2410999 513511444013