Base | Representation |
---|---|
bin | 10111010110100001010000… |
… | …00001101011100000111111 |
3 | 20201211010200102111011001020 |
4 | 23223100220001223200333 |
5 | 23212314430413114444 |
6 | 301114243425115223 |
7 | 13550003045342664 |
oct | 1353205001534077 |
9 | 221733612434036 |
10 | 51351300519999 |
11 | 153a8a67466247 |
12 | 5914286788b13 |
13 | 2286539b4799c |
14 | c975b80dba6b |
15 | 5e0b726be119 |
hex | 2eb42806b83f |
51351300519999 has 16 divisors (see below), whose sum is σ = 70320106268160. Its totient is φ = 33308379355680.
The previous prime is 51351300519947. The next prime is 51351300520081. The reversal of 51351300519999 is 99991500315315.
It is not a de Polignac number, because 51351300519999 - 29 = 51351300519487 is a prime.
It is a super-3 number, since 3×513513005199993 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51351300512999) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2562822 + ... + 10453260.
It is an arithmetic number, because the mean of its divisors is an integer number (4395006641760).
Almost surely, 251351300519999 is an apocalyptic number.
51351300519999 is a deficient number, since it is larger than the sum of its proper divisors (18968805748161).
51351300519999 is a wasteful number, since it uses less digits than its factorization.
51351300519999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7949110.
The product of its (nonzero) digits is 7381125, while the sum is 60.
The spelling of 51351300519999 in words is "fifty-one trillion, three hundred fifty-one billion, three hundred million, five hundred nineteen thousand, nine hundred ninety-nine".
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