Base | Representation |
---|---|
bin | 10111010110100001010000… |
… | …00001101011100000001011 |
3 | 20201211010200102111010222022 |
4 | 23223100220001223200023 |
5 | 23212314430413114242 |
6 | 301114243425115055 |
7 | 13550003045342561 |
oct | 1353205001534013 |
9 | 221733612433868 |
10 | 51351300519947 |
11 | 153a8a674661aa |
12 | 5914286788a8b |
13 | 2286539b4795c |
14 | c975b80dba31 |
15 | 5e0b726be0d2 |
hex | 2eb42806b80b |
51351300519947 has 2 divisors, whose sum is σ = 51351300519948. Its totient is φ = 51351300519946.
The previous prime is 51351300519943. The next prime is 51351300520081. The reversal of 51351300519947 is 74991500315315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51351300519947 - 22 = 51351300519943 is a prime.
It is a super-3 number, since 3×513513005199473 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (51351300519941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25675650259973 + 25675650259974.
It is an arithmetic number, because the mean of its divisors is an integer number (25675650259974).
Almost surely, 251351300519947 is an apocalyptic number.
51351300519947 is a deficient number, since it is larger than the sum of its proper divisors (1).
51351300519947 is an equidigital number, since it uses as much as digits as its factorization.
51351300519947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2551500, while the sum is 53.
The spelling of 51351300519947 in words is "fifty-one trillion, three hundred fifty-one billion, three hundred million, five hundred nineteen thousand, nine hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.141 sec. • engine limits •