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5135433 = 31711811
BaseRepresentation
bin10011100101110001001001
3100122220111020
4103211301021
52303313213
6302023053
761436052
oct23456111
910586436
105135433
112998366
121877a89
1310aa624
14979729
156b6923
hex4e5c49

5135433 has 4 divisors (see below), whose sum is σ = 6847248. Its totient is φ = 3423620.

The previous prime is 5135423. The next prime is 5135437. The reversal of 5135433 is 3345315.

It is a happy number.

5135433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5135433 - 25 = 5135401 is a prime.

It is a D-number.

It is not an unprimeable number, because it can be changed into a prime (5135437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 855903 + ... + 855908.

It is an arithmetic number, because the mean of its divisors is an integer number (1711812).

Almost surely, 25135433 is an apocalyptic number.

It is an amenable number.

5135433 is a deficient number, since it is larger than the sum of its proper divisors (1711815).

5135433 is a wasteful number, since it uses less digits than its factorization.

5135433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1711814.

The product of its digits is 2700, while the sum is 24.

The square root of 5135433 is about 2266.1493772477. The cubic root of 5135433 is about 172.5277754056.

The spelling of 5135433 in words is "five million, one hundred thirty-five thousand, four hundred thirty-three".

Divisors: 1 3 1711811 5135433