Base | Representation |
---|---|
bin | 101111110101011010… |
… | …100100111101111111 |
3 | 11220120111201020010221 |
4 | 233311122210331333 |
5 | 1320142134302333 |
6 | 35332334242211 |
7 | 3465541004056 |
oct | 576532447577 |
9 | 156514636127 |
10 | 51362025343 |
11 | 1a867584932 |
12 | 9b55056367 |
13 | 4ac6cb3795 |
14 | 26b359939d |
15 | 1509237d2d |
hex | bf56a4f7f |
51362025343 has 4 divisors (see below), whose sum is σ = 51362490688. Its totient is φ = 51361560000.
The previous prime is 51362025311. The next prime is 51362025347. The reversal of 51362025343 is 34352026315.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 51362025343 - 25 = 51362025311 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 51362025299 and 51362025308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51362025347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37330 + ... + 322672.
It is an arithmetic number, because the mean of its divisors is an integer number (12840622672).
Almost surely, 251362025343 is an apocalyptic number.
51362025343 is a deficient number, since it is larger than the sum of its proper divisors (465345).
51362025343 is a wasteful number, since it uses less digits than its factorization.
51362025343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 465344.
The product of its (nonzero) digits is 64800, while the sum is 34.
The spelling of 51362025343 in words is "fifty-one billion, three hundred sixty-two million, twenty-five thousand, three hundred forty-three".
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