Base | Representation |
---|---|
bin | 111010011001011010100011… |
… | …1011100000111110111111101 |
3 | 2111100202000202202111020211022 |
4 | 1310302311013130013313331 |
5 | 1014311402242434114313 |
6 | 5020251030523233525 |
7 | 213124113204431456 |
oct | 16462650734076775 |
9 | 2440660682436738 |
10 | 513666402254333 |
11 | 1397407748a95a9 |
12 | 4973bba69788a5 |
13 | 190806c2c52c53 |
14 | 90bb82d5b812d |
15 | 3e5b996749c08 |
hex | 1d32d47707dfd |
513666402254333 has 8 divisors (see below), whose sum is σ = 514309208548608. Its totient is φ = 513023916808144.
The previous prime is 513666402254281. The next prime is 513666402254339. The reversal of 513666402254333 is 333452204666315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 513666402254333 - 232 = 513662107287037 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513666402254339) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 77008010 + ... + 83412027.
It is an arithmetic number, because the mean of its divisors is an integer number (64288651068576).
Almost surely, 2513666402254333 is an apocalyptic number.
It is an amenable number.
513666402254333 is a deficient number, since it is larger than the sum of its proper divisors (642806294275).
513666402254333 is a wasteful number, since it uses less digits than its factorization.
513666402254333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160424043.
The product of its (nonzero) digits is 27993600, while the sum is 53.
The spelling of 513666402254333 in words is "five hundred thirteen trillion, six hundred sixty-six billion, four hundred two million, two hundred fifty-four thousand, three hundred thirty-three".
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