Base | Representation |
---|---|
bin | 10111010111001000000100… |
… | …01001110000101000000011 |
3 | 20201220010110202112101112210 |
4 | 23223210002021300220003 |
5 | 23213140120311042410 |
6 | 301132011342153203 |
7 | 13551341342445363 |
oct | 1353440211605003 |
9 | 221803422471483 |
10 | 51372139940355 |
11 | 154068908001a3 |
12 | 5918321882803 |
13 | 22884ab3c8250 |
14 | c985d3a909a3 |
15 | 5e1491e9c220 |
hex | 2eb902270a03 |
51372139940355 has 32 divisors (see below), whose sum is σ = 88519818562560. Its totient is φ = 25290422593920.
The previous prime is 51372139940309. The next prime is 51372139940357. The reversal of 51372139940355 is 55304993127315.
It is not a de Polignac number, because 51372139940355 - 210 = 51372139939331 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51372139940295 and 51372139940304.
It is not an unprimeable number, because it can be changed into a prime (51372139940357) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7992306 + ... + 12908184.
It is an arithmetic number, because the mean of its divisors is an integer number (2766244330080).
Almost surely, 251372139940355 is an apocalyptic number.
51372139940355 is a deficient number, since it is larger than the sum of its proper divisors (37147678622205).
51372139940355 is a wasteful number, since it uses less digits than its factorization.
51372139940355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4969491.
The product of its (nonzero) digits is 15309000, while the sum is 57.
The spelling of 51372139940355 in words is "fifty-one trillion, three hundred seventy-two billion, one hundred thirty-nine million, nine hundred forty thousand, three hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •