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51372139940357 is a prime number
BaseRepresentation
bin10111010111001000000100…
…01001110000101000000101
320201220010110202112101112212
423223210002021300220011
523213140120311042412
6301132011342153205
713551341342445365
oct1353440211605005
9221803422471485
1051372139940357
11154068908001a5
125918321882805
1322884ab3c8252
14c985d3a909a5
155e1491e9c222
hex2eb902270a05

51372139940357 has 2 divisors, whose sum is σ = 51372139940358. Its totient is φ = 51372139940356.

The previous prime is 51372139940309. The next prime is 51372139940371. The reversal of 51372139940357 is 75304993127315.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39103085536516 + 12269054403841 = 6253246^2 + 3502721^2 .

It is a cyclic number.

It is not a de Polignac number, because 51372139940357 - 26 = 51372139940293 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51372139940296 and 51372139940305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51372139940057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25686069970178 + 25686069970179.

It is an arithmetic number, because the mean of its divisors is an integer number (25686069970179).

Almost surely, 251372139940357 is an apocalyptic number.

It is an amenable number.

51372139940357 is a deficient number, since it is larger than the sum of its proper divisors (1).

51372139940357 is an equidigital number, since it uses as much as digits as its factorization.

51372139940357 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21432600, while the sum is 59.

The spelling of 51372139940357 in words is "fifty-one trillion, three hundred seventy-two billion, one hundred thirty-nine million, nine hundred forty thousand, three hundred fifty-seven".