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5140433201 is a prime number
BaseRepresentation
bin1001100100110010…
…01100100100110001
3111021020122001200212
410302121030210301
541011422330301
62210025153505
7241245650501
oct46231144461
914236561625
105140433201
1121a8705602
12bb562b895
1363bc8b167
1436a9b9a01
152014464bb
hex13264c931

5140433201 has 2 divisors, whose sum is σ = 5140433202. Its totient is φ = 5140433200.

The previous prime is 5140433183. The next prime is 5140433209. The reversal of 5140433201 is 1023340415.

5140433201 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5115682576 + 24750625 = 71524^2 + 4975^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5140433201 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (5140433209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2570216600 + 2570216601.

It is an arithmetic number, because the mean of its divisors is an integer number (2570216601).

Almost surely, 25140433201 is an apocalyptic number.

It is an amenable number.

5140433201 is a deficient number, since it is larger than the sum of its proper divisors (1).

5140433201 is an equidigital number, since it uses as much as digits as its factorization.

5140433201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 5140433201 is about 71696.8144410894. The cubic root of 5140433201 is about 1725.8375210197.

Adding to 5140433201 its reverse (1023340415), we get a palindrome (6163773616).

The spelling of 5140433201 in words is "five billion, one hundred forty million, four hundred thirty-three thousand, two hundred one".