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514101444121 is a prime number
BaseRepresentation
bin1110111101100101101…
…01010111111000011001
31211010222121120021222201
413132302311113320121
531410334432202441
61032101442050201
752066625113336
oct7366265277031
91733877507881
10514101444121
11189035954151
1283777649961
1339630787855
141ac4dd8598d
15d58db03c31
hex77b2d57e19

514101444121 has 2 divisors, whose sum is σ = 514101444122. Its totient is φ = 514101444120.

The previous prime is 514101444083. The next prime is 514101444127. The reversal of 514101444121 is 121444101415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 449119786896 + 64981657225 = 670164^2 + 254915^2 .

It is a cyclic number.

It is not a de Polignac number, because 514101444121 - 27 = 514101443993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 514101444121.

It is not a weakly prime, because it can be changed into another prime (514101444127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257050722060 + 257050722061.

It is an arithmetic number, because the mean of its divisors is an integer number (257050722061).

Almost surely, 2514101444121 is an apocalyptic number.

It is an amenable number.

514101444121 is a deficient number, since it is larger than the sum of its proper divisors (1).

514101444121 is an equidigital number, since it uses as much as digits as its factorization.

514101444121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2560, while the sum is 28.

Adding to 514101444121 its reverse (121444101415), we get a palindrome (635545545536).

The spelling of 514101444121 in words is "five hundred fourteen billion, one hundred one million, four hundred forty-four thousand, one hundred twenty-one".