Base | Representation |
---|---|
bin | 111010011100110011100111… |
… | …1000100001000011010000001 |
3 | 2111102101120221021212012200112 |
4 | 1310321213033010020122001 |
5 | 1014342021412214300101 |
6 | 5021245120415201105 |
7 | 213202564324146530 |
oct | 16471471704103201 |
9 | 2442346837765615 |
10 | 514132534134401 |
11 | 139900424125236 |
12 | 497b63b5516195 |
13 | 190b564a510670 |
14 | 90d620c76c317 |
15 | 3e68b78d7e6bb |
hex | 1d399cf108681 |
514132534134401 has 16 divisors (see below), whose sum is σ = 634774650284544. Its totient is φ = 405502943667264.
The previous prime is 514132534134379. The next prime is 514132534134403. The reversal of 514132534134401 is 104431435231415.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-514132534134401 is a prime.
It is a super-2 number, since 2×5141325341344012 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (514132534134403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8911340345 + ... + 8911398038.
It is an arithmetic number, because the mean of its divisors is an integer number (39673415642784).
Almost surely, 2514132534134401 is an apocalyptic number.
It is an amenable number.
514132534134401 is a deficient number, since it is larger than the sum of its proper divisors (120642116150143).
514132534134401 is a wasteful number, since it uses less digits than its factorization.
514132534134401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17822738720.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 514132534134401 its reverse (104431435231415), we get a palindrome (618563969365816).
The spelling of 514132534134401 in words is "five hundred fourteen trillion, one hundred thirty-two billion, five hundred thirty-four million, one hundred thirty-four thousand, four hundred one".
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