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514132534134403 is a prime number
BaseRepresentation
bin111010011100110011100111…
…1000100001000011010000011
32111102101120221021212012200121
41310321213033010020122003
51014342021412214300103
65021245120415201111
7213202564324146532
oct16471471704103203
92442346837765617
10514132534134403
11139900424125238
12497b63b5516197
13190b564a510672
1490d620c76c319
153e68b78d7e6bd
hex1d399cf108683

514132534134403 has 2 divisors, whose sum is σ = 514132534134404. Its totient is φ = 514132534134402.

The previous prime is 514132534134379. The next prime is 514132534134431. The reversal of 514132534134403 is 304431435231415.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-514132534134403 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 514132534134403.

It is not a weakly prime, because it can be changed into another prime (514132534134463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257066267067201 + 257066267067202.

It is an arithmetic number, because the mean of its divisors is an integer number (257066267067202).

Almost surely, 2514132534134403 is an apocalyptic number.

514132534134403 is a deficient number, since it is larger than the sum of its proper divisors (1).

514132534134403 is an equidigital number, since it uses as much as digits as its factorization.

514132534134403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1036800, while the sum is 43.

Adding to 514132534134403 its reverse (304431435231415), we get a palindrome (818563969365818).

The spelling of 514132534134403 in words is "five hundred fourteen trillion, one hundred thirty-two billion, five hundred thirty-four million, one hundred thirty-four thousand, four hundred three".