Base | Representation |
---|---|
bin | 10111011000011110101010… |
… | …10000001110010101000011 |
3 | 20202001120110211020012000101 |
4 | 23230033111100032111003 |
5 | 23214420324103103134 |
6 | 301205220525303231 |
7 | 13554605421465235 |
oct | 1354172520162503 |
9 | 222046424205011 |
10 | 51418631300419 |
11 | 15424578985119 |
12 | 5925337704b17 |
13 | 228c9aa294b66 |
14 | c9a964414255 |
15 | 5e27b37c9e14 |
hex | 2ec3d540e543 |
51418631300419 has 2 divisors, whose sum is σ = 51418631300420. Its totient is φ = 51418631300418.
The previous prime is 51418631300317. The next prime is 51418631300551. The reversal of 51418631300419 is 91400313681415.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51418631300419 - 231 = 51416483816771 is a prime.
It is a super-2 number, since 2×514186313004192 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51418631300119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25709315650209 + 25709315650210.
It is an arithmetic number, because the mean of its divisors is an integer number (25709315650210).
Almost surely, 251418631300419 is an apocalyptic number.
51418631300419 is a deficient number, since it is larger than the sum of its proper divisors (1).
51418631300419 is an equidigital number, since it uses as much as digits as its factorization.
51418631300419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 46.
The spelling of 51418631300419 in words is "fifty-one trillion, four hundred eighteen billion, six hundred thirty-one million, three hundred thousand, four hundred nineteen".
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