Base | Representation |
---|---|
bin | 100101011010011110110… |
… | …0100110011101110100011 |
3 | 200012120200102002212022111 |
4 | 1022310331210303232203 |
5 | 1133222014340200142 |
6 | 14534130251420151 |
7 | 1040335152405415 |
oct | 112647544635643 |
9 | 20176612085274 |
10 | 5142108912547 |
11 | 1702835476932 |
12 | 6b06a9a54657 |
13 | 2b3b8b8449b9 |
14 | 13ac451009b5 |
15 | 8db5866ae17 |
hex | 4ad3d933ba3 |
5142108912547 has 2 divisors, whose sum is σ = 5142108912548. Its totient is φ = 5142108912546.
The previous prime is 5142108912527. The next prime is 5142108912601. The reversal of 5142108912547 is 7452198012415.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5142108912547 - 219 = 5142108388259 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5142108912547.
It is not a weakly prime, because it can be changed into another prime (5142108912527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2571054456273 + 2571054456274.
It is an arithmetic number, because the mean of its divisors is an integer number (2571054456274).
Almost surely, 25142108912547 is an apocalyptic number.
5142108912547 is a deficient number, since it is larger than the sum of its proper divisors (1).
5142108912547 is an equidigital number, since it uses as much as digits as its factorization.
5142108912547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 806400, while the sum is 49.
The spelling of 5142108912547 in words is "five trillion, one hundred forty-two billion, one hundred eight million, nine hundred twelve thousand, five hundred forty-seven".
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