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51426133 = 114675103
BaseRepresentation
bin1100010000101…
…1001101010101
310120202201101121
43010023031111
5101131114013
65034123541
71163054263
oct304131525
9116681347
1051426133
1127035240
12152805b1
13a867585
146b89433
1547ac58d
hex310b355

51426133 has 4 divisors (see below), whose sum is σ = 56101248. Its totient is φ = 46751020.

The previous prime is 51426127. The next prime is 51426143. The reversal of 51426133 is 33162415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51426133 - 225 = 17871701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51426098 and 51426107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51426113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2337541 + ... + 2337562.

It is an arithmetic number, because the mean of its divisors is an integer number (14025312).

Almost surely, 251426133 is an apocalyptic number.

It is an amenable number.

51426133 is a deficient number, since it is larger than the sum of its proper divisors (4675115).

51426133 is a wasteful number, since it uses less digits than its factorization.

51426133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4675114.

The product of its digits is 2160, while the sum is 25.

The square root of 51426133 is about 7171.2016426817. The cubic root of 51426133 is about 371.8729790442.

Adding to 51426133 its reverse (33162415), we get a palindrome (84588548).

The spelling of 51426133 in words is "fifty-one million, four hundred twenty-six thousand, one hundred thirty-three".

Divisors: 1 11 4675103 51426133